3(y-4)=2(y+1)+6

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Solution for 3(y-4)=2(y+1)+6 equation:


Simplifying
3(y + -4) = 2(y + 1) + 6

Reorder the terms:
3(-4 + y) = 2(y + 1) + 6
(-4 * 3 + y * 3) = 2(y + 1) + 6
(-12 + 3y) = 2(y + 1) + 6

Reorder the terms:
-12 + 3y = 2(1 + y) + 6
-12 + 3y = (1 * 2 + y * 2) + 6
-12 + 3y = (2 + 2y) + 6

Reorder the terms:
-12 + 3y = 2 + 6 + 2y

Combine like terms: 2 + 6 = 8
-12 + 3y = 8 + 2y

Solving
-12 + 3y = 8 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-12 + 3y + -2y = 8 + 2y + -2y

Combine like terms: 3y + -2y = 1y
-12 + 1y = 8 + 2y + -2y

Combine like terms: 2y + -2y = 0
-12 + 1y = 8 + 0
-12 + 1y = 8

Add '12' to each side of the equation.
-12 + 12 + 1y = 8 + 12

Combine like terms: -12 + 12 = 0
0 + 1y = 8 + 12
1y = 8 + 12

Combine like terms: 8 + 12 = 20
1y = 20

Divide each side by '1'.
y = 20

Simplifying
y = 20

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