3(y+2)+2(y-3)=16

Solution for 3(y+2)+2(y-3)=16 equation:

Simplifying
3(y + 2) + 2(y + -3) = 16

Reorder the terms:
3(2 + y) + 2(y + -3) = 16
(2 * 3 + y * 3) + 2(y + -3) = 16
(6 + 3y) + 2(y + -3) = 16

Reorder the terms:
6 + 3y + 2(-3 + y) = 16
6 + 3y + (-3 * 2 + y * 2) = 16
6 + 3y + (-6 + 2y) = 16

Reorder the terms:
6 + -6 + 3y + 2y = 16

Combine like terms: 6 + -6 = 0
0 + 3y + 2y = 16
3y + 2y = 16

Combine like terms: 3y + 2y = 5y
5y = 16

Solving
5y = 16

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '5'.
y = 3.2

Simplifying
y = 3.2