3(y-4)+15=5(y-7)-10

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Solution for 3(y-4)+15=5(y-7)-10 equation: 



3(y-4)+15=5(y-7)-10

We move all terms to the left:

3(y-4)+15-(5(y-7)-10)=0

We multiply parentheses

3y-(5(y-7)-10)-12+15=0



We calculate terms in parentheses: -(5(y-7)-10), so:

5(y-7)-10

We multiply parentheses

5y-35-10

We add all the numbers together, and all the variables

5y-45

Back to the equation:

-(5y-45)



We add all the numbers together, and all the variables

3y-(5y-45)+3=0

We get rid of parentheses

3y-5y+45+3=0

We add all the numbers together, and all the variables

-2y+48=0

We move all terms containing y to the left, all other terms to the right

-2y=-48

y=-48/-2

y=+24

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