(3z+4)=6z-3(3z+2)

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Solution for (3z+4)=6z-3(3z+2) equation:



(3z+4)=6z-3(3z+2)
We move all terms to the left:
(3z+4)-(6z-3(3z+2))=0
We get rid of parentheses
3z-(6z-3(3z+2))+4=0
We calculate terms in parentheses: -(6z-3(3z+2)), so:
6z-3(3z+2)
We multiply parentheses
6z-9z-6
We add all the numbers together, and all the variables
-3z-6
Back to the equation:
-(-3z-6)
We get rid of parentheses
3z+3z+6+4=0
We add all the numbers together, and all the variables
6z+10=0
We move all terms containing z to the left, all other terms to the right
6z=-10
z=-10/6
z=-1+2/3

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