3(y-3)=2(3y+5)

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Solution for 3(y-3)=2(3y+5) equation: 



3(y-3)=2(3y+5)

We move all terms to the left:

3(y-3)-(2(3y+5))=0

We multiply parentheses

3y-(2(3y+5))-9=0



We calculate terms in parentheses: -(2(3y+5)), so:

2(3y+5)

We multiply parentheses

6y+10

Back to the equation:

-(6y+10)



We get rid of parentheses

3y-6y-10-9=0

We add all the numbers together, and all the variables

-3y-19=0

We move all terms containing y to the left, all other terms to the right

-3y=19

y=19/-3

y=-6+1/3

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