2x=(9/5*x)+32

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Solution for 2x=(9/5*x)+32 equation: 



2x=(9/5x)+32

We move all terms to the left:

2x-((9/5x)+32)=0



Domain of the equation: 5x)+32)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2x-((+9/5x)+32)=0

We multiply all the terms by the denominator


2x*5x)+32)-((+9=0

Wy multiply elements

10x^2+9=0

a = 10; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·10·9
Δ = -360
Delta is less than zero, so there is no solution for the equation

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