3(y-3)+y=2(6+2y)

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Solution for 3(y-3)+y=2(6+2y) equation:


Simplifying
3(y + -3) + y = 2(6 + 2y)

Reorder the terms:
3(-3 + y) + y = 2(6 + 2y)
(-3 * 3 + y * 3) + y = 2(6 + 2y)
(-9 + 3y) + y = 2(6 + 2y)

Combine like terms: 3y + y = 4y
-9 + 4y = 2(6 + 2y)
-9 + 4y = (6 * 2 + 2y * 2)
-9 + 4y = (12 + 4y)

Add '-4y' to each side of the equation.
-9 + 4y + -4y = 12 + 4y + -4y

Combine like terms: 4y + -4y = 0
-9 + 0 = 12 + 4y + -4y
-9 = 12 + 4y + -4y

Combine like terms: 4y + -4y = 0
-9 = 12 + 0
-9 = 12

Solving
-9 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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