(2x+5/7x-5)/(3x/7x-5)

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Solution for (2x+5/7x-5)/(3x/7x-5) equation: 


D( x )

((3*x)/7)*x-5 = 0

((3*x)/7)*x-5 = 0

((3*x)/7)*x-5 = 0

3/7*x^2 = 5 // : 3/7

x^2 = 35/3

x^2 = 35/3 // ^ 1/2

abs(x) = (35/3)^(1/2)

x = (35/3)^(1/2) or x = -(35/3)^(1/2)

x in (-oo:-(35/3)^(1/2)) U (-(35/3)^(1/2):(35/3)^(1/2)) U ((35/3)^(1/2):+oo)

(2*x+(5/7)*x-5)/(((3*x)/7)*x-5) = 0

(19/7*x-5)/(3/7*x^2-5) = 0

19/7*x-5 = 0 // + 5

19/7*x = 5 // : 19/7

x = 5/19/7

x = 35/19

x = 35/19

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