3(y-2)=+2(y-2)=

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Solution for 3(y-2)=+2(y-2)= equation: 



3(y-2)=+2(y-2)=

We move all terms to the left:

3(y-2)-(+2(y-2))=0

We multiply parentheses

3y-(+2(y-2))-6=0



We calculate terms in parentheses: -(+2(y-2)), so:

+2(y-2)

determiningTheFunctionDomain
2(y-2)

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)



We get rid of parentheses

3y-2y+4-6=0

We add all the numbers together, and all the variables

y-2=0

We move all terms containing y to the left, all other terms to the right

y=2

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