5(4c-2)+10c-3=-4

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Solution for 5(4c-2)+10c-3=-4 equation: 



5(4c-2)+10c-3=-4

We move all terms to the left:

5(4c-2)+10c-3-(-4)=0

We add all the numbers together, and all the variables

10c+5(4c-2)+1=0

We multiply parentheses

10c+20c-10+1=0

We add all the numbers together, and all the variables

30c-9=0

We move all terms containing c to the left, all other terms to the right

30c=9

c=9/30

c=3/10

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