3(y-2)-2=4(y-4)

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Solution for 3(y-2)-2=4(y-4) equation: 



3(y-2)-2=4(y-4)

We move all terms to the left:

3(y-2)-2-(4(y-4))=0

We multiply parentheses

3y-(4(y-4))-6-2=0



We calculate terms in parentheses: -(4(y-4)), so:

4(y-4)

We multiply parentheses

4y-16

Back to the equation:

-(4y-16)



We add all the numbers together, and all the variables

3y-(4y-16)-8=0

We get rid of parentheses

3y-4y+16-8=0

We add all the numbers together, and all the variables

-1y+8=0

We move all terms containing y to the left, all other terms to the right

-y=-8

y=-8/-1

y=+8

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