3(y-2)-12y=4(2y+7)

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Solution for 3(y-2)-12y=4(2y+7) equation: 



3(y-2)-12y=4(2y+7)

We move all terms to the left:

3(y-2)-12y-(4(2y+7))=0

We add all the numbers together, and all the variables

-12y+3(y-2)-(4(2y+7))=0

We multiply parentheses

-12y+3y-(4(2y+7))-6=0



We calculate terms in parentheses: -(4(2y+7)), so:

4(2y+7)

We multiply parentheses

8y+28

Back to the equation:

-(8y+28)



We add all the numbers together, and all the variables

-9y-(8y+28)-6=0

We get rid of parentheses

-9y-8y-28-6=0

We add all the numbers together, and all the variables

-17y-34=0

We move all terms containing y to the left, all other terms to the right

-17y=34

y=34/-17

y=-2

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