3(y-2)-(Y-1)=-5(2y+1)

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Solution for 3(y-2)-(Y-1)=-5(2y+1) equation: 



3(y-2)-(-1)=-5(2y+1)

We move all terms to the left:

3(y-2)-(-1)-(-5(2y+1))=0

We add all the numbers together, and all the variables

3(y-2)-(-5(2y+1))+1=0

We multiply parentheses

3y-(-5(2y+1))-6+1=0



We calculate terms in parentheses: -(-5(2y+1)), so:

-5(2y+1)

We multiply parentheses

-10y-5

Back to the equation:

-(-10y-5)



We add all the numbers together, and all the variables

3y-(-10y-5)-5=0

We get rid of parentheses

3y+10y+5-5=0

We add all the numbers together, and all the variables

13y=0

y=0/13

y=0

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