3(y-1)=9y+1-2(-5y-7)

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Solution for 3(y-1)=9y+1-2(-5y-7) equation: 



3(y-1)=9y+1-2(-5y-7)

We move all terms to the left:

3(y-1)-(9y+1-2(-5y-7))=0

We multiply parentheses

3y-(9y+1-2(-5y-7))-3=0



We calculate terms in parentheses: -(9y+1-2(-5y-7)), so:

9y+1-2(-5y-7)

determiningTheFunctionDomain
9y-2(-5y-7)+1

We multiply parentheses

9y+10y+14+1

We add all the numbers together, and all the variables

19y+15

Back to the equation:

-(19y+15)



We get rid of parentheses

3y-19y-15-3=0

We add all the numbers together, and all the variables

-16y-18=0

We move all terms containing y to the left, all other terms to the right

-16y=18

y=18/-16

y=-1+1/8

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