3x-2(5+2x)=7+3(2x-4)

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Solution for 3x-2(5+2x)=7+3(2x-4) equation: 



3x-2(5+2x)=7+3(2x-4)

We move all terms to the left:

3x-2(5+2x)-(7+3(2x-4))=0

We add all the numbers together, and all the variables

3x-2(2x+5)-(7+3(2x-4))=0

We multiply parentheses

3x-4x-(7+3(2x-4))-10=0



We calculate terms in parentheses: -(7+3(2x-4)), so:

7+3(2x-4)

determiningTheFunctionDomain
3(2x-4)+7

We multiply parentheses

6x-12+7

We add all the numbers together, and all the variables

6x-5

Back to the equation:

-(6x-5)



We add all the numbers together, and all the variables

-1x-(6x-5)-10=0

We get rid of parentheses

-1x-6x+5-10=0

We add all the numbers together, and all the variables

-7x-5=0

We move all terms containing x to the left, all other terms to the right

-7x=5

x=5/-7

x=-5/7

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