3(y-1)=4y-12

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Solution for 3(y-1)=4y-12 equation: 



3(y-1)=4y-12

We move all terms to the left:

3(y-1)-(4y-12)=0

We multiply parentheses

3y-(4y-12)-3=0

We get rid of parentheses

3y-4y+12-3=0

We add all the numbers together, and all the variables

-1y+9=0

We move all terms containing y to the left, all other terms to the right

-y=-9

y=-9/-1

y=+9

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