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7(x+2)=2(x-3)
We move all terms to the left:
7(x+2)-(2(x-3))=0
We multiply parentheses
7x-(2(x-3))+14=0
We calculate terms in parentheses: -(2(x-3)), so:We get rid of parentheses
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
7x-2x+6+14=0
We add all the numbers together, and all the variables
5x+20=0
We move all terms containing x to the left, all other terms to the right
5x=-20
x=-20/5
x=-4
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