3(y-1)-4=-4(-4y+1)-7y

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Solution for 3(y-1)-4=-4(-4y+1)-7y equation: 



3(y-1)-4=-4(-4y+1)-7y

We move all terms to the left:

3(y-1)-4-(-4(-4y+1)-7y)=0

We multiply parentheses

3y-(-4(-4y+1)-7y)-3-4=0



We calculate terms in parentheses: -(-4(-4y+1)-7y), so:

-4(-4y+1)-7y

We add all the numbers together, and all the variables

-7y-4(-4y+1)

We multiply parentheses

-7y+16y-4

We add all the numbers together, and all the variables

9y-4

Back to the equation:

-(9y-4)



We add all the numbers together, and all the variables

3y-(9y-4)-7=0

We get rid of parentheses

3y-9y+4-7=0

We add all the numbers together, and all the variables

-6y-3=0

We move all terms containing y to the left, all other terms to the right

-6y=3

y=3/-6

y=-1/2

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