-32=3(y-4)-7y

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Solution for -32=3(y-4)-7y equation: 



-32=3(y-4)-7y

We move all terms to the left:

-32-(3(y-4)-7y)=0



We calculate terms in parentheses: -(3(y-4)-7y), so:

3(y-4)-7y

We add all the numbers together, and all the variables

-7y+3(y-4)

We multiply parentheses

-7y+3y-12

We add all the numbers together, and all the variables

-4y-12

Back to the equation:

-(-4y-12)



We get rid of parentheses

4y+12-32=0

We add all the numbers together, and all the variables

4y-20=0

We move all terms containing y to the left, all other terms to the right

4y=20

y=20/4

y=5

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