3(y+9)-3(2y-6)=4y-20

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Solution for 3(y+9)-3(2y-6)=4y-20 equation: 



3(y+9)-3(2y-6)=4y-20

We move all terms to the left:

3(y+9)-3(2y-6)-(4y-20)=0

We multiply parentheses

3y-6y-(4y-20)+27+18=0

We get rid of parentheses

3y-6y-4y+20+27+18=0

We add all the numbers together, and all the variables

-7y+65=0

We move all terms containing y to the left, all other terms to the right

-7y=-65

y=-65/-7

y=9+2/7

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