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2(t+4)=7+5(t-4)
We move all terms to the left:
2(t+4)-(7+5(t-4))=0
We multiply parentheses
2t-(7+5(t-4))+8=0
We calculate terms in parentheses: -(7+5(t-4)), so:We get rid of parentheses
7+5(t-4)
determiningTheFunctionDomain 5(t-4)+7
We multiply parentheses
5t-20+7
We add all the numbers together, and all the variables
5t-13
Back to the equation:
-(5t-13)
2t-5t+13+8=0
We add all the numbers together, and all the variables
-3t+21=0
We move all terms containing t to the left, all other terms to the right
-3t=-21
t=-21/-3
t=+7
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