3(y+8)=-4(3y-4)+5y

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Solution for 3(y+8)=-4(3y-4)+5y equation: 



3(y+8)=-4(3y-4)+5y

We move all terms to the left:

3(y+8)-(-4(3y-4)+5y)=0

We multiply parentheses

3y-(-4(3y-4)+5y)+24=0



We calculate terms in parentheses: -(-4(3y-4)+5y), so:

-4(3y-4)+5y

We add all the numbers together, and all the variables

5y-4(3y-4)

We multiply parentheses

5y-12y+16

We add all the numbers together, and all the variables

-7y+16

Back to the equation:

-(-7y+16)



We get rid of parentheses

3y+7y-16+24=0

We add all the numbers together, and all the variables

10y+8=0

We move all terms containing y to the left, all other terms to the right

10y=-8

y=-8/10

y=-4/5

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