3(z-1)=2z+9

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Solution for 3(z-1)=2z+9 equation: 



3(z-1)=2z+9

We move all terms to the left:

3(z-1)-(2z+9)=0

We multiply parentheses

3z-(2z+9)-3=0

We get rid of parentheses

3z-2z-9-3=0

We add all the numbers together, and all the variables

z-12=0

We move all terms containing z to the left, all other terms to the right

z=12

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