3(y+4)-7y=-28

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Solution for 3(y+4)-7y=-28 equation: 



3(y+4)-7y=-28

We move all terms to the left:

3(y+4)-7y-(-28)=0

We add all the numbers together, and all the variables

-7y+3(y+4)+28=0

We multiply parentheses

-7y+3y+12+28=0

We add all the numbers together, and all the variables

-4y+40=0

We move all terms containing y to the left, all other terms to the right

-4y=-40

y=-40/-4

y=+10

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