3(y+3)=7+2y+2+y3

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Solution for 3(y+3)=7+2y+2+y3 equation:



3(y+3)=7+2y+2+y3
We move all terms to the left:
3(y+3)-(7+2y+2+y3)=0
We add all the numbers together, and all the variables
-(+2y+y^3+7+2)+3(y+3)=0
We multiply parentheses
-(+2y+y^3+7+2)+3y+9=0
We get rid of parentheses
-y^3-2y+3y-7-2+9=0
We do not support eypression: y^3

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