5(h-3)=4(2h-1)-(h+2)

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Solution for 5(h-3)=4(2h-1)-(h+2) equation: 



5(h-3)=4(2h-1)-(h+2)

We move all terms to the left:

5(h-3)-(4(2h-1)-(h+2))=0

We multiply parentheses

5h-(4(2h-1)-(h+2))-15=0



We calculate terms in parentheses: -(4(2h-1)-(h+2)), so:

4(2h-1)-(h+2)

We multiply parentheses

8h-(h+2)-4

We get rid of parentheses

8h-h-2-4

We add all the numbers together, and all the variables

7h-6

Back to the equation:

-(7h-6)



We get rid of parentheses

5h-7h+6-15=0

We add all the numbers together, and all the variables

-2h-9=0

We move all terms containing h to the left, all other terms to the right

-2h=9

h=9/-2

h=-4+1/2

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