3(y+2)=5(y-2)

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Solution for 3(y+2)=5(y-2) equation: 



3(y+2)=5(y-2)

We move all terms to the left:

3(y+2)-(5(y-2))=0

We multiply parentheses

3y-(5(y-2))+6=0



We calculate terms in parentheses: -(5(y-2)), so:

5(y-2)

We multiply parentheses

5y-10

Back to the equation:

-(5y-10)



We get rid of parentheses

3y-5y+10+6=0

We add all the numbers together, and all the variables

-2y+16=0

We move all terms containing y to the left, all other terms to the right

-2y=-16

y=-16/-2

y=+8

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