3(y+2)=-7y-34

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Solution for 3(y+2)=-7y-34 equation: 



3(y+2)=-7y-34

We move all terms to the left:

3(y+2)-(-7y-34)=0

We multiply parentheses

3y-(-7y-34)+6=0

We get rid of parentheses

3y+7y+34+6=0

We add all the numbers together, and all the variables

10y+40=0

We move all terms containing y to the left, all other terms to the right

10y=-40

y=-40/10

y=-4

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