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3x(x-2)=14641
We move all terms to the left:
3x(x-2)-(14641)=0
We multiply parentheses
3x^2-6x-14641=0
a = 3; b = -6; c = -14641;
Δ = b2-4ac
Δ = -62-4·3·(-14641)
Δ = 175728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{175728}=\sqrt{16*10983}=\sqrt{16}*\sqrt{10983}=4\sqrt{10983}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{10983}}{2*3}=\frac{6-4\sqrt{10983}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{10983}}{2*3}=\frac{6+4\sqrt{10983}}{6} $
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