3(y+2)+2y=(y-1)+9

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Solution for 3(y+2)+2y=(y-1)+9 equation: 



3(y+2)+2y=(y-1)+9

We move all terms to the left:

3(y+2)+2y-((y-1)+9)=0

We add all the numbers together, and all the variables

2y+3(y+2)-((y-1)+9)=0

We multiply parentheses

2y+3y-((y-1)+9)+6=0



We calculate terms in parentheses: -((y-1)+9), so:

(y-1)+9

We get rid of parentheses

y-1+9

We add all the numbers together, and all the variables

y+8

Back to the equation:

-(y+8)



We add all the numbers together, and all the variables

5y-(y+8)+6=0

We get rid of parentheses

5y-y-8+6=0

We add all the numbers together, and all the variables

4y-2=0

We move all terms containing y to the left, all other terms to the right

4y=2

y=2/4

y=1/2

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