3/(-x+1)=6/(x+4)

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Solution for 3/(-x+1)=6/(x+4) equation: 



3/(-x+1)=6/(x+4)

We move all terms to the left:

3/(-x+1)-(6/(x+4))=0



Domain of the equation: (-x+1)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-1

x!=-1/-1

x!=1

x∈R





Domain of the equation: (x+4))!=0

x∈R



We add all the numbers together, and all the variables

3/(-1x+1)-(6/(x+4))=0

We calculate fractions


3x/((-1x+1)*(x+4)))+(-(6*(-1x+1))/((-1x+1)*(x+4)))=0



We calculate terms in parentheses: -(6*(-1x+1))/((-1x+1)*(x+4))), so:

6*(-1x+1))/((-1x+1)*(x+4))

We multiply all the terms by the denominator


6*(-1x+1))

We multiply parentheses

-6x+

We add all the numbers together, and all the variables

-6x

Back to the equation:

-(-6x)



We get rid of parentheses

3x/((-1x+1)*(x+4)))+(+6x=0

We multiply all the terms by the denominator


3x+6x*((-1x+1)*(x+4)))+(=0

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