3(y+2)+2(y-5)=15

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Solution for 3(y+2)+2(y-5)=15 equation: 



3(y+2)+2(y-5)=15

We move all terms to the left:

3(y+2)+2(y-5)-(15)=0

We multiply parentheses

3y+2y+6-10-15=0

We add all the numbers together, and all the variables

5y-19=0

We move all terms containing y to the left, all other terms to the right

5y=19

y=19/5

y=3+4/5

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