3(y+1)=(y+3)

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Solution for 3(y+1)=(y+3) equation: 



3(y+1)=(y+3)

We move all terms to the left:

3(y+1)-((y+3))=0

We multiply parentheses

3y-((y+3))+3=0



We calculate terms in parentheses: -((y+3)), so:

(y+3)

We get rid of parentheses

y+3

Back to the equation:

-(y+3)



We get rid of parentheses

3y-y-3+3=0

We add all the numbers together, and all the variables

2y=0

y=0/2

y=0

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