3(y+1)=(4y-21)

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Solution for 3(y+1)=(4y-21) equation: 



3(y+1)=(4y-21)

We move all terms to the left:

3(y+1)-((4y-21))=0

We multiply parentheses

3y-((4y-21))+3=0



We calculate terms in parentheses: -((4y-21)), so:

(4y-21)

We get rid of parentheses

4y-21

Back to the equation:

-(4y-21)



We get rid of parentheses

3y-4y+21+3=0

We add all the numbers together, and all the variables

-1y+24=0

We move all terms containing y to the left, all other terms to the right

-y=-24

y=-24/-1

y=+24

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