12-4(x-4)=7(x+2)-(9x-8)

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Solution for 12-4(x-4)=7(x+2)-(9x-8) equation: 



12-4(x-4)=7(x+2)-(9x-8)

We move all terms to the left:

12-4(x-4)-(7(x+2)-(9x-8))=0

We multiply parentheses

-4x-(7(x+2)-(9x-8))+16+12=0



We calculate terms in parentheses: -(7(x+2)-(9x-8)), so:

7(x+2)-(9x-8)

We multiply parentheses

7x-(9x-8)+14

We get rid of parentheses

7x-9x+8+14

We add all the numbers together, and all the variables

-2x+22

Back to the equation:

-(-2x+22)



We add all the numbers together, and all the variables

-4x-(-2x+22)+28=0

We get rid of parentheses

-4x+2x-22+28=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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