3(y+1)-7=5y+2(y-10)

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Solution for 3(y+1)-7=5y+2(y-10) equation:


Simplifying
3(y + 1) + -7 = 5y + 2(y + -10)

Reorder the terms:
3(1 + y) + -7 = 5y + 2(y + -10)
(1 * 3 + y * 3) + -7 = 5y + 2(y + -10)
(3 + 3y) + -7 = 5y + 2(y + -10)

Reorder the terms:
3 + -7 + 3y = 5y + 2(y + -10)

Combine like terms: 3 + -7 = -4
-4 + 3y = 5y + 2(y + -10)

Reorder the terms:
-4 + 3y = 5y + 2(-10 + y)
-4 + 3y = 5y + (-10 * 2 + y * 2)
-4 + 3y = 5y + (-20 + 2y)

Reorder the terms:
-4 + 3y = -20 + 5y + 2y

Combine like terms: 5y + 2y = 7y
-4 + 3y = -20 + 7y

Solving
-4 + 3y = -20 + 7y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-7y' to each side of the equation.
-4 + 3y + -7y = -20 + 7y + -7y

Combine like terms: 3y + -7y = -4y
-4 + -4y = -20 + 7y + -7y

Combine like terms: 7y + -7y = 0
-4 + -4y = -20 + 0
-4 + -4y = -20

Add '4' to each side of the equation.
-4 + 4 + -4y = -20 + 4

Combine like terms: -4 + 4 = 0
0 + -4y = -20 + 4
-4y = -20 + 4

Combine like terms: -20 + 4 = -16
-4y = -16

Divide each side by '-4'.
y = 4

Simplifying
y = 4

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