log(x)=1+log(x-1)

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Solution for log(x)=1+log(x-1) equation:


Simplifying
log(x) = 1 + log(x + -1)

Multiply glo * x
glox = 1 + log(x + -1)

Reorder the terms:
glox = 1 + glo(-1 + x)
glox = 1 + (-1 * glo + x * glo)
glox = 1 + (-1glo + glox)

Add '-1glox' to each side of the equation.
glox + -1glox = 1 + -1glo + glox + -1glox

Combine like terms: glox + -1glox = 0
0 = 1 + -1glo + glox + -1glox

Combine like terms: glox + -1glox = 0
0 = 1 + -1glo + 0
0 = 1 + -1glo

Solving
0 = 1 + -1glo

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add 'glo' to each side of the equation.
0 + glo = 1 + -1glo + glo
Remove the zero:
glo = 1 + -1glo + glo

Combine like terms: -1glo + glo = 0
glo = 1 + 0
glo = 1

Divide each side by 'lo'.
g = l-1o-1

Simplifying
g = l-1o-1

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