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3(x2+3)=x=1
We move all terms to the left:
3(x2+3)-(x)=0
We add all the numbers together, and all the variables
3(+x^2+3)-x=0
We add all the numbers together, and all the variables
3(+x^2+3)-1x=0
We multiply parentheses
3x^2-1x+9=0
a = 3; b = -1; c = +9;
Δ = b2-4ac
Δ = -12-4·3·9
Δ = -107
Delta is less than zero, so there is no solution for the equation
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