(2x-7)/5=(5-8x)/3

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Solution for (2x-7)/5=(5-8x)/3 equation: 



(2x-7)/5=(5-8x)/3

We move all terms to the left:

(2x-7)/5-((5-8x)/3)=0

We add all the numbers together, and all the variables

(2x-7)/5-((-8x+5)/3)=0

We calculate fractions


2x/()+(-((-8x+5)*5)/()=0



We calculate terms in parentheses: +(-((-8x+5)*5)/(), so:

-((-8x+5)*5)/(

We multiply all the terms by the denominator


-((-8x+5)*5)



We calculate terms in parentheses: -((-8x+5)*5), so:

(-8x+5)*5

We multiply parentheses

-40x+25

Back to the equation:

-(-40x+25)



We get rid of parentheses

40x-25

Back to the equation:

+(40x-25)



We get rid of parentheses

2x/()+40x-25=0

We multiply all the terms by the denominator


2x+40x*()-25*()=0

We add all the numbers together, and all the variables

2x+40x*()=0

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