-(27x-3)=-((22x-19)-(2-11x))

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Solution for -(27x-3)=-((22x-19)-(2-11x)) equation: 



-(27x-3)=-((22x-19)-(2-11x))

We move all terms to the left:

-(27x-3)-(-((22x-19)-(2-11x)))=0

We add all the numbers together, and all the variables

-(27x-3)-(-((22x-19)-(-11x+2)))=0

We get rid of parentheses

-27x-(-((22x-19)-(-11x+2)))+3=0



We calculate terms in parentheses: -(-((22x-19)-(-11x+2))), so:

-((22x-19)-(-11x+2))



We calculate terms in parentheses: -((22x-19)-(-11x+2)), so:

(22x-19)-(-11x+2)

We get rid of parentheses

22x+11x-19-2

We add all the numbers together, and all the variables

33x-21

Back to the equation:

-(33x-21)



We get rid of parentheses

-33x+21

Back to the equation:

-(-33x+21)



We get rid of parentheses

-27x+33x-21+3=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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