3(x2+2x+1)=-6

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Solution for 3(x2+2x+1)=-6 equation: 



3(x2+2x+1)=-6

We move all terms to the left:

3(x2+2x+1)-(-6)=0

We add all the numbers together, and all the variables

3(+x^2+2x+1)-(-6)=0

We add all the numbers together, and all the variables

3(+x^2+2x+1)+6=0

We multiply parentheses

3x^2+6x+3+6=0

We add all the numbers together, and all the variables

3x^2+6x+9=0

a = 3; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·3·9
Δ = -72
Delta is less than zero, so there is no solution for the equation

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