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3(x-9)(x+25)=0
We multiply parentheses ..
3(+x^2+25x-9x-225)=0
We multiply parentheses
3x^2+75x-27x-675=0
We add all the numbers together, and all the variables
3x^2+48x-675=0
a = 3; b = 48; c = -675;
Δ = b2-4ac
Δ = 482-4·3·(-675)
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10404}=102$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-102}{2*3}=\frac{-150}{6} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+102}{2*3}=\frac{54}{6} =9 $
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