16(b+12)=32b

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Solution for 16(b+12)=32b equation: 



16(b+12)=32b

We move all terms to the left:

16(b+12)-(32b)=0

We add all the numbers together, and all the variables

-32b+16(b+12)=0

We multiply parentheses

-32b+16b+192=0

We add all the numbers together, and all the variables

-16b+192=0

We move all terms containing b to the left, all other terms to the right

-16b=-192

b=-192/-16

b=+12

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