3(x-8)-5=9(x+2)=1

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Solution for 3(x-8)-5=9(x+2)=1 equation: 



3(x-8)-5=9(x+2)=1

We move all terms to the left:

3(x-8)-5-(9(x+2))=0

We multiply parentheses

3x-(9(x+2))-24-5=0



We calculate terms in parentheses: -(9(x+2)), so:

9(x+2)

We multiply parentheses

9x+18

Back to the equation:

-(9x+18)



We add all the numbers together, and all the variables

3x-(9x+18)-29=0

We get rid of parentheses

3x-9x-18-29=0

We add all the numbers together, and all the variables

-6x-47=0

We move all terms containing x to the left, all other terms to the right

-6x=47

x=47/-6

x=-7+5/6

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