2(q-4)+5q=8(q-2)

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Solution for 2(q-4)+5q=8(q-2) equation: 



2(q-4)+5q=8(q-2)

We move all terms to the left:

2(q-4)+5q-(8(q-2))=0

We add all the numbers together, and all the variables

5q+2(q-4)-(8(q-2))=0

We multiply parentheses

5q+2q-(8(q-2))-8=0



We calculate terms in parentheses: -(8(q-2)), so:

8(q-2)

We multiply parentheses

8q-16

Back to the equation:

-(8q-16)



We add all the numbers together, and all the variables

7q-(8q-16)-8=0

We get rid of parentheses

7q-8q+16-8=0

We add all the numbers together, and all the variables

-1q+8=0

We move all terms containing q to the left, all other terms to the right

-q=-8

q=-8/-1

q=+8

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