-6(-5y+2)-8y=4(y-3)-2

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Solution for -6(-5y+2)-8y=4(y-3)-2 equation: 



-6(-5y+2)-8y=4(y-3)-2

We move all terms to the left:

-6(-5y+2)-8y-(4(y-3)-2)=0

We add all the numbers together, and all the variables

-8y-6(-5y+2)-(4(y-3)-2)=0

We multiply parentheses

-8y+30y-(4(y-3)-2)-12=0



We calculate terms in parentheses: -(4(y-3)-2), so:

4(y-3)-2

We multiply parentheses

4y-12-2

We add all the numbers together, and all the variables

4y-14

Back to the equation:

-(4y-14)



We add all the numbers together, and all the variables

22y-(4y-14)-12=0

We get rid of parentheses

22y-4y+14-12=0

We add all the numbers together, and all the variables

18y+2=0

We move all terms containing y to the left, all other terms to the right

18y=-2

y=-2/18

y=-1/9

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