3(x-7)+2=11(x-6-2x)-4

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Solution for 3(x-7)+2=11(x-6-2x)-4 equation: 



3(x-7)+2=11(x-6-2x)-4

We move all terms to the left:

3(x-7)+2-(11(x-6-2x)-4)=0

We add all the numbers together, and all the variables

3(x-7)-(11(-1x-6)-4)+2=0

We multiply parentheses

3x-(11(-1x-6)-4)-21+2=0



We calculate terms in parentheses: -(11(-1x-6)-4), so:

11(-1x-6)-4

We multiply parentheses

-11x-66-4

We add all the numbers together, and all the variables

-11x-70

Back to the equation:

-(-11x-70)



We add all the numbers together, and all the variables

3x-(-11x-70)-19=0

We get rid of parentheses

3x+11x+70-19=0

We add all the numbers together, and all the variables

14x+51=0

We move all terms containing x to the left, all other terms to the right

14x=-51

x=-51/14

x=-3+9/14

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