1/3(24r+3)=10r

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Solution for 1/3(24r+3)=10r equation: 



1/3(24r+3)=10r

We move all terms to the left:

1/3(24r+3)-(10r)=0



Domain of the equation: 3(24r+3)!=0

r∈R



We add all the numbers together, and all the variables

-10r+1/3(24r+3)=0

We multiply all the terms by the denominator


-10r*3(24r+3)+1=0

Wy multiply elements

-30r^2(2+1=0

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