3(x-5)=7x+21

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Solution for 3(x-5)=7x+21 equation: 



3(x-5)=7x+21

We move all terms to the left:

3(x-5)-(7x+21)=0

We multiply parentheses

3x-(7x+21)-15=0

We get rid of parentheses

3x-7x-21-15=0

We add all the numbers together, and all the variables

-4x-36=0

We move all terms containing x to the left, all other terms to the right

-4x=36

x=36/-4

x=-9

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