3(c+1)=2(c-1)-4

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Solution for 3(c+1)=2(c-1)-4 equation: 



3(c+1)=2(c-1)-4

We move all terms to the left:

3(c+1)-(2(c-1)-4)=0

We multiply parentheses

3c-(2(c-1)-4)+3=0



We calculate terms in parentheses: -(2(c-1)-4), so:

2(c-1)-4

We multiply parentheses

2c-2-4

We add all the numbers together, and all the variables

2c-6

Back to the equation:

-(2c-6)



We get rid of parentheses

3c-2c+6+3=0

We add all the numbers together, and all the variables

c+9=0

We move all terms containing c to the left, all other terms to the right

c=-9

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